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Q.

A massless string of length l passes over a frictionless pulley whose axis is horizontal. Two monkeys hang from the ends of the string at the same distance l/2 from the pulley, the monkeys start climbing upward simultaneously. First monkey climbs with a speed v relative to the string and the second with a speed 2v. Both monkeys have equal masses. Then the time taken by the first and second monkey is meeting each other are respectively

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a

lvand l2v

b

l2vand l4v

c

l4vand l2v

d

l3vand l3v

answer is A.

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Detailed Solution

 Speed of approach=v-(-2v)=3v t=l3v

each one have same time.

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