A massless string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

a=m1−m2m1+m2g⇒g8=m1−m2m1+m2g⇒m1m2=97

A massless string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

a=m1−m2m1+m2g⇒g8=m1−m2m1+m2g⇒m1m2=97

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A massless string passing over a smooth light pulley connects two blocks of masses m₁ and m₂ (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

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8 : 1

5 : 3

9 : 7

4 : 3

answer is B.

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$a = (\frac{m_{1} - m_{2}}{m_{1} + m_{2}}) g \Rightarrow \frac{g}{8} = (\frac{m_{1} - m_{2}}{m_{1} + m_{2}}) g$
$\Rightarrow \frac{m_{1}}{m_{2}} = \frac{9}{7}$

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A massless string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

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A massless string passing over a smooth light pulley connects two blocks of masses m₁ and m₂ (vertically). If the acceleration of the system is g/8 then the ratio of the masses is