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A mass $m$ is fixed at x=a on a parabolic wire with its axis vertical and vertex at the origin as shown in the figure. The equation of parabola is $x^{2} = 4$ ay. The wire frame is rotating with constant angular velocity $ω$ about Y-axis. The acceleration of the bead is

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zero

$\frac{a}{4} ω^{2}$

${aω}^{2}$

$\frac{ω^{2}}{a}$

answer is B.

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Detailed Solution

The bead is moving on a circular path of radius $a$ .

So, the acceleration is ${aω}^{2}$ .

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