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Q.

A material ‘B’ has twice the specific resistance of ‘A’. A circular wire made of ‘B’ has twice the diameter of a wire made of ‘A’. Then for the two wires to have the same resistance, the ratio lB / lA of their respective lengths must be

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a

1/4

b

2

c

1

d

1/2

answer is D.

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Detailed Solution

R=ρlπr2∴l∝r2ρlBlA=ρAρB×rB2rA2;lBlA=ρA2ρA×4rA2rA2=2

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