A material of resistivity $ρ$ is formed in the shape of truncated cone of altitude ‘h’ as shown in the fig. the top end has radius ‘a’ while bottom ‘b’. Assuming a uniform current density through any circular cross section of the cone. The resistance between two ends is :

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$\frac{ρh}{ab}$

$\frac{ρh}{πab}$

$\frac{ρa}{πhb}$

$\frac{ρb}{πah}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$E f f e c t i v e a r e a o f f r u s t u m A= \sqrt{A_{1} A_{2}} = \sqrt{{πa}^{2} {.πb}^{2}} =πab$

$N o w a p p l y f o r m u l a o f r e s i s \tan c e ∴ R= \frac{ρh}{A} = \frac{ρh}{πab}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE