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A measured temperature on Fahrenheit scale is 200 F. What will this reading be on celsius scale?

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40^oC

94^oC

93.3^oC

30^oC

answer is C.

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Detailed Solution

$\begin{array}{l} ^{\circ} F = \frac{9}{5} t^{\circ} C + 32 \\ 200 - 32 = \frac{9}{5} t^{\circ} C \\ \Rightarrow \frac{9}{5} t^{\circ} C = 168 \\ t^{\circ} C = \frac{168 \times 5}{9} = 93 {.3}^{\circ} C \end{array}$

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