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Q.

A mechanic strikes a nail with a hammer of mass of 500 g moving with a velocity of 20 m/s. The hammer comes to rest in 0.02 s after striking the nail. Calculate the force exerted by the nail on the hammer.


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a

40 N

b

50 N

c

20 N

d

30 N 

answer is B.

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Detailed Solution

According to the first law of motion:
F = m x a
=> F = m (v - u) / t
On substituting the values, we get the force as
=> F = 0.5 (0 - 20) / 0.02
=> F = -1 / 0.02
=> F = -50 N
 
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