A mechanic strikes a nail with a hammer of mass of 500 g moving with a velocity of 20 m/s. The hammer comes to rest in 0.02 s after striking the nail. Calculate the force exerted by the nail on the hammer.

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A mechanic strikes a nail with a hammer of mass of 500 g moving with a velocity of 20 m/s. The hammer comes to rest in 0.02 s after striking the nail. Calculate the force exerted by the nail on the hammer.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

40 N

50 N

20 N

30 N

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

According to the first law of motion:
F = m x a
=> F = m (v - u) / t
On substituting the values, we get the force as
=> F = 0.5 (0 - 20) / 0.02
=> F = -1 / 0.02
=> F = -50 N

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th