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A mercury drop of radius 1 cm is broken into 108 droplets of equal size. The work done is $(T = 35 \times 10^{- 2} N / m)$

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$4 \cdot 35 \times 10^{- 2} J$

$4 \cdot 35 \times 10^{- 3} J$

$4 \cdot 35 \times 10^{- 8} J$

$4 \cdot 35 \times 10^{- 6} J$

answer is A.

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Detailed Solution

$W = 4 {πR}^{2} [n^{1 / 3} - 1] T = 4 \times \frac{22}{7} \times (1 \times 10^{2}) \times [{(10^{6})}^{1 / 3} - 1] (35 \times 10^{- 2}) = 4 \times 22 \times 5 \times 10^{- 6} [99] = 4 \cdot 35 \times 10^{- 2} J$

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