A merry go round has a radius 4m and completes a revolution in 2 seconds. Then acceleration is

Given that r = 4m distance covered to complete one revolution$=\text{S}=\text{2πr}$.

Time taken t = 2s.

$\text{v}=\frac{\text{2}\pi \text{r}}{\text{t}}=\frac{2\pi \times 4}{2}=4\pi$

$\text{a}=\frac{{\text{v}}^{\text{2}}}{\text{r}}=\frac{{\left(4\pi \right)}^2}{4}=\frac{16{\pi }^2}{4}=4{\pi }^2$