A metal baII of mass 2 kg moving with a velocity of 36 km/h has an head-on collision with a stationary ball of 3 kg. If after the collision, the two balls move together, the loss in K.E due to collision is

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A metal baII of mass 2 kg moving with a velocity of 36 km/h has an head-on collision with a stationary ball of 3 kg. If after the collision, the two balls move together, the loss in K.E due to collision is

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40 J

60 J

100 J

140 J

answer is B.

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Detailed Solution

Applying the law of conservation of momentum, we have

$2 \times 10 = (2 + 3) \lor (∵ 36 km / h = 10 m / s) ∴ V = 4 m / s Loss of K.E. = \frac{1}{2} \times 2 \times (10)^{2} - \frac{1}{2} \times 5 \times (4)^{2} = 60 J$