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Q.

A metal ball immersed in alcohol weighs W1 at 0"C and W2 at 50"C. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of the metal is large compared to that of alcohol, it can be shown that:

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a

W1 > W2

b

W1 < W2

c

none of these

d

W1 = W2

answer is .

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Detailed Solution

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As the coefficient of cubical expansion of metal is less as compared to the coefficient of cubical expansion of liquid, we may neglect the expansion of metal ball. So when the ball is immersed in alcohol at 00C and has weight W1,

                    W1 = Wo-0g

Where Wo = weight of ball in air

Similarly, W2 = Wo-V ρ50g

and ρ0 density of alcohol at 00C

As ρ50 < ρ0

 W2 > W1 

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