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A metal ball of $4 kg$ is dropped from a height $of 2.5 m$ . What will the ball's kinetic energy be when it strikes the ground?

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90 J

94 J

98 J

96 J

answer is C.

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Detailed Solution

A metal ball of

4 kg

is dropped from a height

of 2.5 m

. The kinetic energy of the ball when it strikes the ground will be

98 J

The velocity of the ball of mass

4 kg

when dropped from

2.5 m

of height can be calculated by

v^{2} = u^{2} + 2 gh

Given,
Initial velocity,

u = 0

g = 9.8 m / s^{2}

,
height,

h = 2.5 m

So,

v = 7 m / s

Now, Kinetic Energy is a form of energy that an object of mass (

m

) or body has due to virtue of its motion and is formulated as

K . E = \frac{1}{2} m v^{2}

Where

m = mass

of the object and

v = velocity

K . E = \frac{1}{2} \times 4 \times 72

\Rightarrow 98 J

So, when the ball strikes back on the ground, its kinetic energy will be

98 J

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