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A metal ball of mass 2 kg moving with a velocity of 36 km/h has an head on collision with a stationary ball of mass 3 kg. If after the collision, the two balls move together, the loss in kinetic energy due to collision is

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40 J

100 J

140 J

60 J

answer is B.

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Detailed Solution

$v = 36 km / h = 10 m / s$
By law of conservation of momentum
$2 \times 10 = (2 + 3) V \Rightarrow V = 4 m / s$
Loss in K.E. $= \frac{1}{2} \times 2 \times {(10)}^{2} - \frac{1}{2} \times 5 \times {(4)}^{2} = 60 J$

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