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A metal block has length 50 cm, breadth 30 cm and thickness 20 cm. When current passes through it parallel to its length and parallel to its breadth, the ratio of maximum to minimum resistance of that block is

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9 : 25

25 : 4

25 : 9

4 : 25

answer is C.

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Detailed Solution

Parallel to length

$R_{1} = \frac{ρ \times 50}{30 \times 20} = \frac{ρ}{12}$

Parallel to breadth
$R_{2} = \frac{ρ \times 30}{50 \times 20} = \frac{3 ρ}{100}$

$\frac{R_{1}}{R_{2}} = \frac{\frac{ρ}{12}}{\frac{3 ρ}{100}} = \frac{25}{9}$

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