A metal block of mass 3.3kg is heated to a temperature of ${400}^{o}C$ and then block is placed on large ice block. The specific heat of the metal is $0.4J{g}^{-1}{K}^{-1}$ and heat of fusion of water is $330J{g}^{-1}.$ The maximum amount of ice that can melt is

Given, mass of metal block, m = 33kg
Temperature,  $\Delta t={400}^{o}C$
Specific heat of metal block,  $s_m=0.4J{g}^{-1}{K}^{-1}=400J{g}^{-1}{K}^{-1}$ 
Latent heat of fusion,  $L_f=330J{g}^{-1}=3.3\times {10}^{5}Jk{g}^{-1}$
 If m be the maximum amount of mass of melted ice, then  
$$\begin{gathered} m^{\text{'}}{L}_f=m{s}_m\Delta T \\ \Rightarrow m^{\text{'}}{L}_f=\frac{m{s}_m\Delta T}{L_f}=\frac{3.3\times 400\times 400}{3.3\times {10}^5}=1.6kg \end{gathered}$$