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Q.

A metal crystallizes in fcc  arrangement with edge length equal to 400 nm. Calculate maximum possible radius of the atom which can fit in the voids without disturbing the crystal structure?

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a

165.6 nm

b

39 nm

c

71.71 nm

d

58.55 nm

answer is D.

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Detailed Solution

For tetrahedral voids, rR=0.225

For octahedral voids, rR=0.414

For FCC,

R=a22=40022rR=0.414⇒r=0.414×40022=58.55pm

Diameter is 2r=2×58.55=117.1 pm

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