Questions  

A metal exposed to light of wavelength 800 nm and emits photoelectrons with a certain kinetic energy. The maximum kinetic energy of photo-electron doubles when light of wavelength 500 nm is used. The work function of the metal is (Take hc = 1230 eV-nm).

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By Expert Faculty of Sri Chaitanya
a
1.537 eV
b
2.46 eV
c
0.615 eV
d
1.23 eV
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detailed solution

Correct option is C

k1=1230800ϕ                       ...(1)k2=2k1=1230500ϕ             ...(2)

Eliminating k1 from (1) and (2) we get

0=12305001230400+ϕϕ=0.615eV

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