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Q.

A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72g cm–3. The molar mass of the metal is :- (NA Avogadro constant= 6.02 × 1023mol-1)

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a

20g mol-1

b

27g mol-1

c

40g mol-1

d

30g mol-1

answer is D.

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Detailed Solution

d=2.72gcm−3 

z = no. of effective constituent particles in one unit cell

M = molecular weight

a=404pm edge length of unit cell

Density of cubic unit cell-

d  =​ ZM / a3NA

d = 27 g / mol

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