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A metal M crystallises in a face-centred cubic lattice. Consider an atom N which occupies an interstitial site without changing radius of atom M. If the edge length of the crystal is 3.61 A⁰ and it is given that N is the largest atom that can fit in the interstitialsite, then the radius of the atom is………. A⁰.

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1.26

0.53

5.3

1.5

answer is B.

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Detailed Solution

$rov = 0.414 \times \frac{a}{2 \sqrt{2}} = \frac{0.414 \times 3.61}{2 (1.41)} = 0.53 A^{0}$

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