A metal ‘M’ reacts with nitrogen gas to afford‘M₃N’. ‘M₃N’ on heating at high temperaturegives back ‘M’ and on reaction with waterproduces a gas ‘B’. Gas ‘B’ reacts withaqueous solution of CuSO₄ to form a deep blue compound. ‘M’ and ‘B’ respectively are

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Al and N₂

Ba and N₂

Na and NH₃

Li and NH₃

answer is A.

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Detailed Solution

Li and NH₃
The metal ‘M’ forms nitride M3N. Since N has valency 3, metal ‘M’ has valence 1. Hence, ‘M’ can be either Li or Na. So we can rule out Ba and Al.

M₃N reacts with water to produce gas ‘B’. This is given by Li
Li₃N+3H₂O→3LiOH+NH₃
Thus, gas ‘B’ is ammonia

Ammonia reacts with aqueous CuSO₄ solution to form deep blue compound [Cu(NH₃)₄]SO₄
NH₃+CuSO₄→[Cu(NH₃)₄]SO₄