Q.

A metal ‘M’ reacts with nitrogen gas to afford‘M3N’. ‘M3N’ on heating at high temperaturegives back ‘M’ and on reaction with waterproduces a gas ‘B’. Gas ‘B’ reacts withaqueous solution of CuSO4 to form a deep blue compound. ‘M’ and ‘B’ respectively are 
 

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a

Al and N2 
 

b

Ba and N
 

c

Na and NH
 

d

Li and NH3 
 

answer is A.

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Detailed Solution

Li and NH3
The metal ‘M’ forms nitride M3​N. Since N has valency 3, metal ‘M’ has valence 1. Hence, ‘M’ can be either Li or Na. So we can rule out Ba and Al.

M3​N reacts with water to produce gas ‘B’. This is given by Li
Li3​N+3H2​O→3LiOH+NH3​
Thus, gas ‘B’ is ammonia

Ammonia reacts with aqueous CuSO4​ solution to form deep blue compound [Cu(NH3​)4​]SO4​
NH3​+CuSO4​→[Cu(NH3​)4​]SO4​

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A metal ‘M’ reacts with nitrogen gas to afford‘M3N’. ‘M3N’ on heating at high temperaturegives back ‘M’ and on reaction with waterproduces a gas ‘B’. Gas ‘B’ reacts withaqueous solution of CuSO4 to form a deep blue compound. ‘M’ and ‘B’ respectively are