A metal plate of area $1\times {10}^{-4} {\mathrm{m}}^2$ is illuminated by a radiation of intensity $16 \raisebox{1ex}{$\mathrm{mW}$}\!\left/ \!\raisebox{-1ex}{${\mathrm{m}}^2$}\right.$. The work function of the metal is $5 \mathrm{eV}$. The energy of the incident photons is $10 \mathrm{eV}$ and only $10\%$ of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be $\left[1 \mathrm{eV}=1.6\times {10}^{-19} \mathrm{J}\right]$