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Q.

A metal rod of length 10x has its one end A in ice at 0°C and the other end B in water at 100°C . If a point P on the Rod is maintained at 400°C. Then it is found that equal amounts of water and ice evaporates and melts per unit time. If the point   'P'  is at a distance of   'λx' from the ice end. Then the value of   'λ'  is 

 (LV of water =540cal/g) (Lf of ice =80cal/g) 

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a

12

b

9

c

6

d

3

answer is B.

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Detailed Solution

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The heat flows per unit time
Q=KA(400θ)(10λ)=mLfusion(1)
Heat flow from 'P' to 'B' is 
Q=KA(400100)(10λ)x=mLvap(2)
Dividing (1)&(2), we get
400(10λ)300λ=LfusLvap=80454027

404λ3λ=427

On solving λ=9 

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