Q.

A metal rod of length L having uniform cross section area A and variable linear mass density λx=λ0(1+xL),x  is measured from the end A. Rod is placed on a smooth horizontal surface. A constant force  F0  is applied at end B. Young’s modulus of rod is Y, the value of energy stored in the rod will be  1x(19F02L15YA), then x is _______
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answer is 9.

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Detailed Solution

 λx=λo(1+xL)
mx=λo(x+x22L) 
Mass of total rod =λo(32L) 
Acceleration  a=2F3Lλo
Tension at x=x,  Tx=mxa
Tx=2F3Lλoλo(x+x22L) ; Tx=23FL(x+x22L)
U=12(TxA)(TxAy)(Adx) ; U=(12Ay)x=0x=1Tx2dx
 U=19Fo2L135yA

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