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A metal rod of length $l$ moving with an angular velocity $ω$ and velocity of its centre is v. Find potential difference between points $A$ and B at the instant shown in figure. A uniform magnetic field of strength $\vec{B}$ exist perpendicular to the plane of paper :

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$B ω l - \frac{1}{2} B ω l^{2}$

$B v l + \frac{1}{2} B ω l^{2}$

$Bvl+Bω {(l/2)}^{2}$

$B v l$

answer is A.

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Detailed Solution

Here the emf induces only due to translatory motion, and so e = Bvl

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