A metal rod of resistance 20 $Ω$ is fixed along a diameter of a conducting ring of radius 0.1m and lies on x-y plane. There is a magnetic field $\vec{B} = (50 T) \hat{k}$ . The ring rotates with an angular velocity $ω$ = 20 $r a d / s e c$ about its axis. An external resistance of 10 $Ω$ is connected across the center of the ring and rim. The current through external resistance is

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$\frac{1}{4}$

$\frac{1}{2}$

$\frac{1}{3}$

Zero

answer is C.

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Detailed Solution

$ε = \frac{B ω r^{2}}{2} = 5 V o l t$ . Now current $I = \frac{ε}{R_{1} + R_{2}}$ = $\frac{1}{3} A$

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