A metal vessel of negligible heat capacity contains 0.5 kg of water (of specific heat capacity $4200 J k g^{- 1} K^{- 1}$ ). It is heated from $15^{0} C t o 85^{0} C$ by 750W immersion heater in 4 minutes. The average loss of heat in watts to the surroundings from the vessel during this time is

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answer is 137.5.

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Detailed Solution

$\begin{array}{l} P t - Q_{s y s t e m +} Q_{\begin{array}{l} l a s t \end{array}} \\ 750 \times 4 \times 60 = 0.5 \times 4200 \times 70 + Q_{l a s t} \\ ∴ P_{l a s t} = \frac{Q_{l o s t}}{t i m e} \end{array}$

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