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Q.

A metal wire of length 0.5 m and cross-sectional area 10-4 m2  has breaking stress 5×108Nm2.  A block 10kg is attached at one end of the string and is rotating in a horizontal circle. The maximum linear velocity of block will be _________m/s.

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Detailed Solution

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T=mv2l=10×v20.5=20v2

Tmax= Breaking stress × area  =5×108×104=5×104

20v2=5×104

v2=14×104

v=50m/s

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A metal wire of length 0.5 m and cross-sectional area 10-4 m2  has breaking stress 5×108Nm−2.  A block 10kg is attached at one end of the string and is rotating in a horizontal circle. The maximum linear velocity of block will be _________m/s.