A metallic rod breaks when strain produced is 0.2%.The Young's modulus of the material of the rod is 7x l09 N/m2. What should be its area of cross-section to support a load of 104N ?

Maximum possible strain = 0.2/100∴ A=FY× strain =104×1007×109×0⋅2=7⋅1×10−4m2

A metallic rod breaks when strain produced is 0.2%.The Young's modulus of the material of the rod is 7x l09 N/m2. What should be its area of cross-section to support a load of 104N ?

Maximum possible strain = 0.2/100∴ A=FY× strain =104×1007×109×0⋅2=7⋅1×10−4m2

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A metallic rod breaks when strain produced is 0.2%.The Young's modulus of the material of the rod is 7x l0⁹N/m². What should be its area of cross-section to support a load of 10⁴N ?

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7.1 x 10^-8m²

7.1x10^-6m²

7.1 x l0^-4 m²

7.1 x 10^-2m²

answer is C.

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Detailed Solution

Maximum possible strain = 0.2/100
$\begin{array}{l} ∴ A = \frac{F}{Y \times strain} \\ = \frac{10^{4} \times 100}{(7 \times 10^{9}) \times 0 \cdot 2} = 7 \cdot 1 \times 10^{- 4} m^{2} \end{array}$

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A metallic rod breaks when strain produced is 0.2%.The Young's modulus of the material of the rod is 7x l09 N/m2. What should be its area of cross-section to support a load of 104N ?

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A metallic rod breaks when strain produced is 0.2%.The Young's modulus of the material of the rod is 7x l0⁹N/m². What should be its area of cross-section to support a load of 10⁴N ?