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A metallic rod, having uniform cross-sectional area of $2 c m^{2}$ is subjected to a tensile force of 200 KN. If young's modulus of the metal is $2 \times 10^{6} N / c m^{2}$ , find the strain produced in the rod.

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0.015

0.04

0.005

0.05

answer is D.

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Detailed Solution

Tensile stress $σ = \frac{200 \times 10^{3}}{2} N / c m^{2} = 10^{5} N / c m^{2}$

Strain $\in = \frac{σ}{Y} = \frac{10^{5}}{2 \times 10^{6}} = 0.05$

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