Q.

A metallic rod of length l  , linear mass density μ  rotates about one of its end ‘O’ in a smooth horizontal plane with an angular velocity ω  about an end axis which is perpendicular to plane of rotation shown in figure. A transverse pulse generated at the free end P to reach the axis of rotation.  (neglect the gravitational effect). 

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a

The speed of the transverse pulse when it reaches the midpoint of sting with respect to ground is    
5lω8

b

The tension in the string at a distance ‘x’ from the free end   μ[l2(lx)2]2ω2

c

The speed of the transverse pulse just after generated at the free end point P with respect to ground is  lω  
 

d

The time taken by the transverse pulse to reach the axis of rotation from free end is  π2ω

answer is A, B, C, D.

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Detailed Solution

Tension =μ(l2(lx)2)ω22  
Transverse velocity of pulse w.r.t to the string  =ωl2(lx)22
Transverse velocity of pulse at the free and =lω 
Transverse velocity of pulse at the mid of string =3l2ω28+l2ω24=58lω

dxdt=ω2l2(lx)22dxωl2(lx)2=0tdtt=π2ω
 
 
 

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