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A metallic rod of mass per unit length 0.5kgm^–1 is lying horizontally on a smooth inclined plane which makes an angle of 30^o with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction 0.25 T is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is

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11.32 A

5.98 A

7.14 A

14.76 A

answer is C.

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Detailed Solution

$Bil \cos θ = mgsin θ$
Question Image
( $∵$ liner denstiy µ=m/ l;m = µl )
$i = \frac{m g}{lB} \tan θ = \frac{0 .5 \times 10}{0 .25} \tan (30^{\circ}) = 11 .56 A$

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