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A metallic sheet, in the form of a square ABCD, has non-uniform distribution of mass. Two forces 10 N and 20 N are applied on the sheet as shown in figure. It is observed that the sheet makes only translational motion. Then distance of centre of mass from the corner A may be

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$5 cm$

$6 cm$

$\sqrt{17} cm$

$\sqrt{11} cm$

answer is B.

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Detailed Solution

Since the sheet does not make any rotational motion, lines of action of 10 N and 20 N forces must pass through the centre of mass G of the sheet as shown in the figure.

$∴ AG = \sqrt{3^{2} + 4^{2}} cm = 5 cm$

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