A metallic spherical shell has inner radius R₁ and outer radius R₂. A charge Q is placed at the centre of the shell. The surface charge density on the inner surface, and outer surface of shell are respectively

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$\frac{- Q}{4 π R_{1}^{2}} a n d \frac{- Q}{4 π R_{2}^{2}}$

$\frac{Q}{4 π R_{1}^{2}} a n d \frac{Q}{4 π R_{2}^{2}}$

$\frac{Q}{4 π R_{2}^{2}} a n d \frac{- Q}{4 π R_{1}^{2}}$

$\frac{- Q}{4 π R_{1}^{2}} a n d \frac{Q}{4 π R_{2}^{2}}$

answer is A.

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Detailed Solution

The induced charge on the inner surface is -Q and outer surface is +Q, hence the surface charge density on the inner surface, and outer surface of shell are respectively $\frac{- Q}{4 π R_{1}^{2}} a n d \frac{Q}{4 π R_{2}^{2}}$

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