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Q.

A meter bridge with two resistances connected in the two gaps has a balance point at 40 cm. If a resistance 10 Ω is connected in series with the smaller resistor, the balance point shifts by 20 cm. Neglecting any corrections, the larger resistance

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a

12 Ω

b

40 Ω

c

60 Ω

d

8 Ω

answer is D.

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Detailed Solution

 R1R2=40100−40
 and  R1+10R2=60100−60⇒ R2 = 12  Ω

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