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A metre scale measures correct lengths at 0⁰C. Using this scale length of an object is measured as 15 m at 40⁰C. Then the correct length of that object is $(α = 20 \times 10^{- 6} /^{0} C)$

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15.12 cm

15.02 m

15.012 cm

15.008 m

answer is C.

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Detailed Solution

$l_{m} = \frac{l_{t r u e}}{1 + α_{s c} Δ θ}$

$\begin{array}{l} l_{t r u e} = l_{m} [1 + α_{s c} (θ_{m} - θ_{c})] \\ = 15 c m [1 + 2 \times 10^{- 5} (40 - 0)] =15.012cm \end{array}$

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