A metre stick is balanced on a knife edge at its centre. When two coins, each of mass 5 g are put one on of the other at the 12 cm mark, the stick is found to balanced at 45 cm. The mass of the metre stick is

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76 g

66 g

36 g

56 g

answer is B.

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Detailed Solution

Let m be the mass of the metre stick concentrated at C, the 50 cm mark as shown in the figure.

In equilibrium, taking moments of forces about C; we get

$10 g (45 - 12) = mg (50 - 45)$

$10 g \times 33 = mg \times 5$

$m = \frac{10 \times 33}{5} = 66 g$

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