A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index 53is poured inside the bucket, then microscope have to be raised by 30 cm to focus the object again. The height of the liquid in the bucket is:

S=t1−1μ30=t1−35⇒⇒30=t25t=75cm

S=t1−1μ30=t1−35⇒⇒30=t25t=75cm

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A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index $\frac{5}{3}$ is poured inside the bucket, then microscope have to be raised by 30 cm to focus the object again. The height of the liquid in the bucket is:

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12 cm

18 cm

50 cm

75 cm

answer is D.

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$\begin{array}{l} S = t (1 - \frac{1}{μ}) \\ 30 = t (1 - \frac{3}{5}) \Rightarrow\Rightarrow 30 = t (\frac{2}{5}) \\ t = 75 cm \end{array}$

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