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Q.

A mixture containing 0.05 mole of K2Cr2O7, and 0.02 mole of KMnO4 was treated with excess of Kl in acidic medium. The liberated iodine required 1.0 L of Na2S2O3 solution for titration. Concentration of Na2S2O3 solution was:

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a

0.25 mol L-1

b

0.30 mol L-1

c

0.20 mol L-1

d

0.40 mol L-1

answer is A.

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Detailed Solution

eq. wt. of K2Cr2O7= molar mass 6
eq. wt. of KMnO4= molar mass 5
eq. of Na2S2O3 = eq. of I2libeIated
                           = eq. of KMnO4 + eq. of K2Cr2O7
or N x 1= 0.02 x 5 + 0.05 x 6
= N = 0.4 or M=0.4

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