A mixture contains $6\mathrm{g}$ of  (+)-2-butanol  and $4\mathrm{g}$ of (-)- 2-butanol. What will be the enantiomeric excess (e.e)

Enantiomeric axis $=\frac{\text{ mole of one enantiomer }-\text{ mole of other enantiomer }}{\text{ Total moles of both enantiomers }}$$=\frac{6-4}{10}\times 100=\frac{2}{10}\times 100=20\mathrm{\%}$