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Q.

A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?

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a

11.2 L

b

44.8 L

c

22.4 L

d

67.2 L

answer is A.

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Detailed Solution

2 g of hydrogen = 1 mole, 32 g of O2= 1 mole
Total volume of 2 moles of gases at NTP
=2 x 22.4 L = 44.8 L

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