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Q.

A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H2SO4. The evolved gaseous  mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be

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a

3.0

b

2.8

c

1.4

d

4.4

answer is C.

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Detailed Solution

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HCOOH Formic acid  Conc. H2SO4CO+H2O
(COOH oxalic acid )2 Conc. H2SO4CO+CO2+H2O
CO remains at STP.
CO from 4.5 g of oxalic acid
=4.590×28=1.4g
CO from 2.3 g of formic acid
=2.346×28=1.4g
Weight of CO = 1.4 + 1.4 = 2.8 g

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