Q.

A mixture of 2-butanolenantiomersshowed a specific rotation of +6.760. The enantiomeric excess of (+) 2-butanol is 10x%. The value of x is..------(specific rotation of pure (+)-2-butanol is 13.520)

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answer is 5.

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Detailed Solution

Enantiomeric excess =+6.76+13.52×100

=50  %

10x=50

x=5

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