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Q.

A mixture of 2 moles of N2 and 8 moles of H2 are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 0.4 moles of N2  was present. The equilibrium concentration of  H2 will be

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a

4 mole/lit

b

1.6 mole/lit

c

1 mole/lit

d

2 mole/lit

answer is C.

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Detailed Solution

N2+3H22NH3

Initial :          2         8        0 

Acc.to eqn    x        3x     2x Equilibrium: 2 - x   8-3x   2x

At equilibrium; 0.4 moles of N2 are present.

2 - x = 0.4 

x =1.6moles.

Equilibrium: 0.4   3.2   3.2 N2     H2   NH3

So equilibrium ionic of H2=nH2V(H)=3.22=1.6 mole/lit.

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