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Q.

A mixture of 25% O2, 35% N2 and 40% CO2 by mass exerts a total pressure of 700mm Hg. The partial pressures of these gases follows the order

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a

PO2>pCO2>pN2

b

PN2>PO2>PCO2

c

PN2>PCO2>PO2

d

PO2>pN2>PCO2

answer is D.

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Detailed Solution

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Partial pressure=mole fraction×total pressure

For O2, n=2532=0.78 For N2, n=3528=1.25 For CO2, n=4044=0.91

More the number of moles, more the mole fraction, which implies more the value of partial pressure.

So, the correct order is: PN2>PCO2>PO2

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