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Q.

A mixture of A and B show positive deviation from Raoult’s law when

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a

ΔVmix=0, ΔSmix>0

b

ΔVmix<0, ΔSmix=0

c

A – B interaction is stronger than A – A and B – B interaction

d

A – B interaction is weaker than A – A and B – B interaction

answer is B.

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Detailed Solution

When A – B interaction is weaker than  A – A and B – B interaction, then the mixture of A and B shows positive deviation.

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