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A mixture of chlorides of copper, cadmium, chromium, iron and aluminium was dissolved in water. It was acidified with dilute HCl and then hydrogen sulphide gas was passed for sufficient time. It was filtered, boiled and a few drops of nitric acid were added, while boiling. To this solution, ammonium chloride and ammonium hydroxide were added. To this excess of sodium hydroxide was added and then filtered. The filtrate shall give test for:

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sodium and iron

sodium, iron, cadmium and aluminium

aluminium and iron

sodium, chromium and aluminium

answer is B.

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Detailed Solution

When $Al (OH)_{3}$ dissolve in NaOH the following reaction is obtained,

$NaOH + Al (OH)_{3} \to {NaAlO}_{2} + 2 H_{2} O$

When $Al (OH)_{3}$ dissolve in NaOH precipitate of ${NaAlO}_{2}$ is obtained.

Therefore, ${NaAlO}_{2}$ will be present in the filtrate.

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