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Q.

A mixture of ethane and ethene occupies 16.42 L at 1 atm and at 400 K. The mixture reacts completely with 51.2 g of O₂ to produce CO₂ and H₂O. Assuming ideal gas behaviour, calculate the mole fractions of C₂H₆ and C₂H₄ in the mixture.

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a

0.3, 0.2

b

0.66, 0.33

c

0.75, 0.25

d

0.4, 0.6

answer is D.

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Detailed Solution

$\begin{array}{l} PV = nRT \\ (1) (16.42) = n (0.0821) (400) \\ n = 0.5 moles \end{array}$
If no.of moles of Ethane = x, then no.of moles of Ethene = (0.5-x)
Total volume of oxygen required for combustion = 1+1.5x
$\begin{array}{l} 1 + 1.5 x = 1.6 \\ x = 0.4 \\ (1 - x) = 0.6 \end{array}$

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