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Q.

A mixture of ethane and ethene occupies 16.42 L at 1 atm and at 400 K. The mixture reacts completely with 51.2 g of O2 to produce CO2 and H2O. Assuming ideal gas behaviour, calculate the mole fractions of C2H6 and C2H4 in the mixture.

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a

0.4, 0.6

b

0.66, 0.33

c

0.75, 0.25

d

0.3, 0.2

answer is D.

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Detailed Solution

PV=nRT(1)(16.42)=n(0.0821)(400)n=0.5  moles
If no.of moles of Ethane = x, then no.of moles of Ethene = (0.5-x)
Total volume of oxygen required for combustion = 1+1.5x
1+1.5x=1.6x=0.4(1−x)=0.6

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