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A mixture of H₂ , He and O₂ with mass ratio equal to the ratio of their atomic weight is present in compartment-II of a cylinder as shown in figure. The SPM is fixed by stoppers such that it divide the cylinder into three equal parts. Find the ratio of pressure in the three parts at equilibrium
[If your answer is $a : b : c$ then fill in OMR sheet as $a + b + c$ . For example if $2 : 6 : 8$ then $1 + 3 + 4 = 8$ ]

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answer is 12.

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Detailed Solution

Initially, compartment Il has

$n_{H_{2}} : n_{He} : n_{O_{2}} :: \frac{1}{2} : \frac{4}{4} : \frac{16}{32}$

Finally

$\begin{array}{l} I : n_{H_{2}} = \frac{a}{6} \\ II : n_{O_{2}} = \frac{a}{2} \\ n_{H_{2}} = \frac{a}{6} \\ n_{He} = \frac{a}{2} \\ III : n_{H_{2}} = \frac{a}{6} \end{array}$

$\begin{array}{l} n_{He} = \frac{a}{2} \\ P_{I} : P_{II} : P_{III} = \frac{a}{6} : \frac{7 a}{6} : \frac{4 a}{6} \Rightarrow 1 : 7 : 4 \end{array}$

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