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Q.

A mixture of hydrogen and oxygen has volume $2000 {cm}^{3}$ , temperature $300 K$ , pressure $100 kPa$ and mass $0.76 g$ The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be :

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a

1/16

b

⅓

c

16/1

d

3/1

answer is B.

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Detailed Solution

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$PV = nRT n = \frac{100 \times 10^{3} \times 2000 \times 10^{- 6}}{\frac{25}{3} \times 300} n = 80 \times 10^{- 3} n_{1} + n_{2} = 0.08 n_{1} \times 2 + n_{2} \times 32 = 0.76 (0.08 - n_{2}) 2 + n_{2} (32) = 0.76 n_{2} = 0.02 n_{1} = 0.06 \frac{n_{1}}{n_{2}} = \frac{3}{1}$

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