Q.

A mixture of ideal gases 7kg of nitrogen and 11 kg of CO2 . Then 

(Take γ for nitrogen and CO2 as 1.4 and 1.3 respectively)

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a

equivalent molecular weight of the mixture is 36

b

equivalent molecular weight of the mixture is 18

c

γ for the mixture is 5/2

d

γ for the mixture is 47/35

answer is A, D.

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Detailed Solution

M=M12+M21+1=28+442=36

n1+n2γmix 1=n1γ11+n2γ21

 14+14γmix 1=1/41.41+1/41.31

or

2γmix1=10.4+10.3

 γmix1.343

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