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A mixture of ideal gases $7 k g$ of nitrogen and $11 k g$ of $C O_{2}$ . Then
(Take $γ$ for nitrogen and $C O_{2}$ as 1.4 and 1.3 respectively)

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equivalent molecular weight of the mixture is 36

equivalent molecular weight of the mixture is 18

$γ$ for the mixture is $5 / 2$

$γ$ for the mixture is $47 / 35$

answer is A, D.

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Detailed Solution

$M = \frac{M_{12} + M_{2}}{1 + 1} = \frac{28 + 44}{2} = 36$

$\frac{n_{1} + n_{2}}{γ_{mix} - 1} = \frac{n_{1}}{γ_{1} - 1} + \frac{n_{2}}{γ_{2} - 1}$

$∴ \frac{\frac{1}{4} + \frac{1}{4}}{γ_{mix} - 1} = \frac{1 / 4}{1.4 - 1} + \frac{1 / 4}{1.3 - 1}$

$[\frac{2}{γ_{m i x} - 1}] = \frac{1}{0.4} + \frac{1}{0.3}$

$∴ γ_{m i x} ≃ 1.343$

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